At 25°C,ΔG° = -198 kJ for the reaction,NO(g)+ O₃(g)⇌ NO₂(g)+ O₂(g). Calculate ΔG under the following conditions:

Question

Quizplus · Accepted Answer

ΔG = ΔG° + RTln(Q)
Since the reaction is at equilibrium, Q = Kp
ΔG = ΔG° + RTln(Kp)
At 25°C, R = 8.31 J/mol·K and T = 298 K
ΔG = -198 kJ + (8.31 J/mol·K)(298 K)ln(Kp)
Kp = e^(-198000 J/mol / (8.31 J/mol·K × 298 K)) = 0.368
ΔG = -198 kJ + (8.31 J/mol·K)(298 K)ln(0.368) = -159 kJ
Therefore, the best choice is A, ΔG = -159 kJ.

At 25°C,ΔG° = -198 KJ for the Reaction,NO(g)+ O3(g)⇌ NO2(g)

At 25°C,ΔG° = -198 KJ for the Reaction,NO(g)+ O₃(g)⇌ NO₂(g)