For the hypothetical reaction A + 2 B^x → A^y + 2 B,E° = 1.50 V = and ΔG° = -305 kJ.For this reaction,if the value of x is 4,then the value of y = .

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For this reaction, using the Nernst equation we have: ΔG = ΔG° + RT ln Q ΔG° = -nFE° where n is the number of electrons transferred, F is Faraday's constant, and Q is the reaction quotient. Since E° = 1.50 V and ΔG° = -305 kJ/mol, we have: -305 kJ/mol = -nF(1.50 V) Solving for n, we get: n = 2 So the reaction involves the transfer of 2 electrons. From the given reaction, we can see that A is getting oxidized (losing electrons) and B^x is getting reduced (gaining electrons). If x is 4, it means B⁴ is getting 4 electrons added to it. So, y = 4/2 = 2. Therefore, the answer is B.

For the Hypothetical Reaction a + 2 Bx → Ay

For the Hypothetical Reaction a + 2 B^x → A^y