Consider the following galvanic cell.
-What is the quantitative change in the cell voltage on increasing the ion concentration in the anode compartment by a factor of 10?

Question

Consider the following galvanic cell. 
-What is the quantitative change in the cell voltage on increasing the ion concentration in the anode compartment by a factor of 10?

Quizplus · Accepted Answer

According to the Nernst equation, the cell potential is given by:
Ecell = E°cell - (RT/nF) ln(Q)
where E°cell is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons transferred in the cell reaction, F is the Faraday constant, and Q is the reaction quotient.
On increasing the ion concentration in the anode compartment by a factor of 10, the reaction quotient Q would increase by a factor of 10 as well. This would result in a negative logarithmic term, which would decrease the cell potential. Since the anode compartment is where oxidation occurs and the anode is the negative electrode in this cell, the cell potential would decrease. Therefore, the correct answer is C, -0.03 V.

Consider the Following Galvanic Cell