Consider the following standard reduction potentials, Zn²⁺(aq) + 2 e^- → Zn(s) E° = -0.76 V
I₂(s) + 2 e^- → 2 I^-(aq) E° = +0.54 V
Under standard conditions,

Question

Consider the following standard reduction potentials, Zn²⁺(aq)+ 2 e^- → Zn(s)E° = -0.76 V I₂(s)+ 2 e^- → 2 I^-(aq)E° = +0.54 V Under standard conditions,

Quizplus · Accepted Answer

The standard reduction potential of I₂(s) is higher than Zn²⁺(aq), indicating that I₂(s) is a stronger oxidizing agent than Zn²⁺(aq). Similarly, the standard reduction potential of Zn(s) is higher than that of I^-(aq), indicating that Zn(s) is a stronger reducing agent than I^-(aq). Therefore, option B is the correct choice.

Consider the Following Standard Reduction Potentials, Zn2+(aq)+ 2 E- →

Consider the Following Standard Reduction Potentials, Zn²⁺(aq)+ 2 E^- →