How many kilograms of copper sulfide must be reduced to produce 3.20 × 10¹⁰ kg of Cu? The reduction of copper proceeds via the following reaction. Cu₂S (l)+ O₂ (g)2Cu (l)+ SO₂ (g) A)3.20 × 10¹³kg B)4.0 × 10¹²kg C)6.4 × 10¹⁰ kg D)1.3 × 10¹¹ kg

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Quizplus · Accepted Answer

The stoichiometry of the reaction indicates that 1 mole of Cu2S produces 2 moles of Cu. Given that the molar mass of Cu2S (159.16 g/mol) and Cu (63.546 g/mol), to produce 3.20 × 10^1 kg (or 3200 kg) of Cu, the mass of Cu2S required is calculated by first finding the moles of Cu produced and then using the stoichiometry to find the moles of Cu2S needed. Since 2 moles of Cu come from 1 mole of Cu2S, and the mass of Cu2S is higher than that of Cu, more mass of Cu2S is needed than the mass of Cu produced. The calculation aligns with option A, 3.20 × 10^13 kg, considering the molar ratios and the masses involved.

How Many Kilograms of Copper Sulfide Must Be Reduced to Produce