If 55.0 g of olive oil has 877 cal of heat added to it at a room temperature of 26.0°C,what will be the final temperature of the olive oil? The specific heat of olive oil is 2.19 cal/g°C.

Question

Quizplus · Accepted Answer

We can use the formula q = mCΔT, where q is the heat added, m is the mass of the olive oil, C is the specific heat, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔT: ΔT = q / (mC). Substituting the given values, we get ΔT = 877 cal / (55.0 g * 2.19 cal/g°C) = 7.283°C. We need to add this temperature change to the initial temperature of 26.0°C to find the final temperature: final temperature = 26.0°C + 7.283°C = 33.3°C. Therefore, the answer is A.

If 550 G of Olive Oil Has 877 Cal of Heat