How many molecules are present in 1.36 g of AgNO₃?

Name: How many molecules are present in 1.36 g of AgNO 3 ?
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Question

Quizplus · Accepted Answer

1.36 g of AgNO₃ is equal to 0.00389 moles (using the molar mass of AgNO₃ which is 350.95 g/mol). One molecule of AgNO₃ contains 21 atoms (Ag-1, N-1, O-2, S-1). Therefore, the total number of molecules in 1.36 g of AgNO₃ is equal to: (6.022 x 10^23) * 0.00389 / 21 = 1.1 x 10^21 = 4.82 × 10²¹ (rounded to two significant figures)

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