When a monosaccharide forms a cyclic hemiacetal,the carbon atom that contained the carbonyl group is identified as the ________ carbon atom because
A) D; the carbonyl group is drawn to the right.
B) L; the carbonyl group is drawn to the left.
C) anomeric; its substituents can assume an α or a β position.
D) acetal; it forms bonds to an -OR and an -OR'.
E) enantiomeric; depending on its position,the resulting ring can have a mirror image.
Correct Answer:
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Q21: A hemiacetal linkage consists of a
A)carbon atom
Q25: All of the statements concerning monosaccharides are
Q31: A sugar is classified as an L-isomer
Q32: The conversion of cyclic glucose between the
Q39: A glycosidic bond is
A)a bond between any
Q50: _ of glucose leads to gluconic acid.
A)Oxidation
B)Reduction
C)Isomerization
D)Glycosidation
E)Esterification
Q51: Common reducing reactions of monosaccharides are due
Q53: The bond connecting the two monosaccharides in
Q57: Lactose results from reacting glucose at its
Q60: Which molecule is not a reducing sugar?
A)lactose
B)maltose
C)sucrose
D)glucose
E)galactose
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