If 55.0 g of olive oil has 877 cal of heat added to it at a room temperature of 26.0°C,what will be the final temperature of the olive oil? The specific heat of olive oil is 2.19 cal/g°C.
A)33.3°C
B)7.3°C
C)19.0°C
D)26.0°C
E)3.3 °C

Question

Quizplus · Accepted Answer

The heat added to the olive oil can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat added, $m$ is the mass, $c$ is the specific heat, and $\Delta T$ is the change in temperature. Rearranging the formula to solve for $\Delta T$, we get $\Delta T = \frac{q}{mc}$. Plugging in the given values, $\Delta T = \frac{877 \, \text{cal}}{55.0 \, \text{g} \times 2.19 \, \text{cal/g°C}} = 7.3°C$. To find the final temperature, add the change in temperature to the initial temperature: $26.0°C + 7.3°C = 33.3°C$.

If 550 G of Olive Oil Has 877 Cal of Heat