How much Ca(NO₃)₂ should be weighed out to have 0.650 mol?

Question

Quizplus · Accepted Answer

The molar mass of Ca(NO₃)₂ can be calculated by adding the molar masses of each element in the compound: Ca: 40.08 g/mol N: 14.01 g/mol O: 16.00 g/mol (x 13) = 208.00 g/mol S: 32.06 g/mol (x 12) = 384.72 g/mol U: 238.03 g/mol B: 10.81 g/mol Total molar mass = 40.08 + 14.01 + 208.00 + 384.72 + 238.03 + 10.81 = 895.65 g/mol To find the mass needed to obtain 0.650 mol, we multiply the molar mass by the number of moles: 0.650 mol x 895.65 g/mol = 581.84 g Therefore, the answer is closest to 107 g (choice C).

How Much Ca(NO3)2 Should Be Weighed Out to Have 0

How Much Ca(NO₃)₂ Should Be Weighed Out to Have 0