A 65 mL sample of argon gas has a temperature of 325°C.What will the temperature be in °C when the volume of the gas is decreased to 25 mL at constant pressure?

Question

Quizplus · Accepted Answer

According to the combined gas law, P1V1/T1 = P2V2/T2, where P is pressure, V is volume, and T is temperature. As the pressure is constant, we can simplify the equation to V1/T1 = V2/T2.

So, V1/T1 = V2/T2

65mL/325°C = 25mL/T2

T2= (25mL x 325°C)/65mL

T2= 125°C

Therefore, the temperature will be 125°C when the volume is decreased to 25 mL.

A 65 ML Sample of Argon Gas Has a Temperature