A sample of helium has a volume of 480 mL at 47.0°C and 740 mm Hg.The temperature is lowered to 22.0°C and the pressure to 625 mm Hg.What is the new volume?

Question

Quizplus · Accepted Answer

We can use the combined gas law to solve for the new volume:

(P₁V₁/T₁) = (P₂V₂/T₂)

Substituting the given values:

(740 mmHg)(480 mL)/(47.0°C + 273.15) = (625 mmHg)(V₂)/(22.0°C + 273.15)

Solving for V₂:

V₂ = [(740 mmHg)(480 mL)/(47.0°C + 273.15)]/[(625 mmHg)/(22.0°C + 273.15)]

V₂ = 524 mL

Therefore, the new volume is 524 mL, which corresponds to choice C.

A Sample of Helium Has a Volume of 480 ML