Normal saline is 0.920% (w/v)NaCl in water.How many grams of NaCl are needed to prepare 15.0 L of normal saline?
A)1.38 g
B)16.3 g
C)53.8 g
D)138 g
E)807 g

Question

Quizplus · Accepted Answer

To prepare 15.0 L of a 0.920% (w/v) NaCl solution, you need 0.920 grams of NaCl per 100 mL of solution. Since there are 15,000 mL in 15 L, you multiply 15,000 mL by 0.920 g/100 mL to find the total grams of NaCl needed: (15,000 mL * 0.920 g/100 mL) = 138 g.

Normal Saline Is 0