The [OH^-] and the pH of 0.035 M KOH at 25°C are,respectively, A)0.035 M and +1.46. B)0.035 M and -1.46. C)2.9 × 10^-13 M and -12.54. D)0.035 and +12.54. E)2.9 × 10^-13 M and +12.54.

Question

Quizplus · Accepted Answer

KOH is a strong base, so it dissociates completely in water. The concentration of OH- ions will be the same as the initial concentration of KOH, which is 0.035 M. The pH can be calculated using the pOH and the relationship pH + pOH = 14 at 25°C. First, find the pOH = -log[OH-] = -log(0.035) ≈ 1.46. Then, pH = 14 - pOH = 14 - 1.46 = 12.54.

The [OH-] and the PH of 0

The [OH^-] and the PH of 0