When ultraviolet photons with a wavelength of 3.45 × 10^-⁷ m are directed at the surface of an unknown metal in vacuum, electrons with a maximum kinetic energy of 1.52 eV are emitted from the surface. What is the work function of the metal? A)3.60 eV B)3.11 eV C)2.59 eV D)2.08 eV E)1.98 eV

Question

Quizplus · Accepted Answer

The work function, φ (phi), is the minimum amount of energy required to remove an electron from the surface of a metal. It can be calculated by subtracting the maximum kinetic energy (EKmax) of the emitted electrons from the energy of the incident photons (hv):

φ = hv - EKmax

h is Planck's constant, and v is the frequency of the incident photons, which can be calculated from the given wavelength:

v = c / λ = (3.00 × 10^8 m/s) / (3.45 × 10^-17 m) = 8.70 × 10^15 Hz

Now we can calculate φ:

φ = (6.626 × 10^-34 J s) × (8.70 × 10^15 Hz) - (1.52 eV × 1.60 × 10^-19 J/eV)
φ = 2.08 eV

Therefore, the answer is D, 2.08 eV.

When Ultraviolet Photons with a Wavelength of 3