The temperature of a 5.00-kg lead brick is increased by 525 C°. If the specific heat capacity of lead is 128 J/(kg ^$\circ$ C°), what is the increase in the mass of the lead brick when it has reached its final temperature?

Question

Quizplus · Accepted Answer

We can use the formula: 
Q = mcΔT
where Q is the heat added, m is the mass of the lead brick, c is the specific heat capacity of lead, and ΔT is the change in temperature.

Q = (5.00 kg)(128 J/(kg·°C))(525°C) = 33,600,000 J

To find the increase in mass, we can use the formula:
Δm = Q/ΔHf
where ΔHf is the heat of fusion, which is 23,000 J/kg for lead.

Δm = (33,600,000 J)/(23,000 J/kg) = 1,460 kg

However, we need to convert this to an increase in mass, which is:
Δm = 1,460 kg - 5.00 kg = 1,455 kg

To express this in scientific notation with two significant figures, we get:
Δm = 3.73 × 10² kg

Therefore, the answer is D.

The Temperature of a 5 ∘\circ∘ C°), What Is the Increase in the Mass of 525

The Temperature of a 5 $\circ$ C°), What Is the Increase in the Mass of 525