A certain type of glass is used in making flat-panel computer monitors. For light with a wavelength in air of 656.3 nm, the refractive index of the glass is n_A = 1.5160. For light with a wavelength in air of 435.8 nm, n_B = 1.5290. Determine the difference, $\lambda$_A- $\lambda$_B, in their wavelengths inside the glass. A)147.9 nm B)156.0 nm C)220.5 nm D)268.4 nm E)293.1 nm

Question

Quizplus · Accepted Answer

The wavelength inside the glass is given by $\lambda = \frac{\lambda_0}{n}$, where $\lambda_0$ is the wavelength in air and $n$ is the refractive index. Calculate $\lambda_A$ and $\lambda_B$ inside the glass and find the difference: $\lambda_A = \frac{656.3}{1.5160}$, $\lambda_B = \frac{435.8}{1.5290}$. The difference is approximately 147.9 nm.

A Certain Type of Glass Is Used in Making Flat-Panel λ\lambdaλ

A Certain Type of Glass Is Used in Making Flat-Panel $\lambda$