The figure shows the time variation of the magnitude of the electric field of an electromagnetic wave produced by a wire antenna. -What is the peak value of the magnetic field? A)1.4 × 10^-⁸ T B)2.3 × 10^-⁸ T C)3.3 × 10^-⁸ T D)4.6 × 10^-⁸ T E)5.4 × 10^-⁸ T

Question

Quizplus · Accepted Answer

The peak value of the magnetic field can be obtained using the equation B = E/c, where E is the peak value of the electric field and c is the speed of light. From the graph, we can see that the peak value of the electric field is approximately 3.3 × 10^18 V/m. The speed of light is approximately 3 × 10^8 m/s. Therefore, the peak value of the magnetic field is B = E/c = (3.3 × 10^18)/(3 × 10^8) = 1.1 × 10^-5 T, which is equivalent to 3.3 × 10^6 µT or 3.3 mT. The closest answer choice is C, which is 3.3 × 10^1 µT or 3.3 × 10^-2 mT, so it is the correct choice.

The Figure Shows the Time Variation of the Magnitude of the Electric