A battery is manufactured to have an emf of 24.0 V, but the terminal voltage is only 22.0 V when the battery is connected across a 10.0-$\varOmega$ resistor. What is the internal resistance of the battery?
A)3.9 $\varOmega$
B)0.46 $\varOmega$
C)1.2 $\varOmega$
D)0.91$\varOmega$
E)0.68 $\varOmega$

Question

Quizplus · Accepted Answer

We can use the formula V = E - IR, where V is the terminal voltage, E is the emf, I is the current, and R is the internal resistance.

Substituting the given values, we get:

22.0 V = 24.0 V - I * R

Solving for R, we get:

R = (24.0 V - 22.0 V) / I

We can find I using Ohm's law: I = V / R, where V is the voltage and R is the resistance.

Substituting the given values, we get:

I = 22.0 V / 10.0 Ω = 2.2 A

Substituting I back into the equation for R, we get:

R = (24.0 V - 22.0 V) / 2.2 A = 0.91 Ω

Therefore, the internal resistance of the battery is 0.91 Ω. Answer choice D is the correct choice.

A Battery Is Manufactured to Have an Emf of 24 Ω\varOmegaΩ

A Battery Is Manufactured to Have an Emf of 24 $\varOmega$