Two point charges are separated by 1.00 × 10-2 m. One charge is -2.8 × 10-8 C; and the other is +2.8 × 10-8 C. The points A and B are located 2.5 × 10-3 m from the lower and upper point charges as shown.
-If a proton, which has a charge of +1.60 × 10^-¹⁹ C, is moved from rest at A to rest at B, what is change in electrical potential energy of the proton?

Question

Two point charges are separated by 1.00 × 10-2 m. One charge is -2.8 × 10-8 C; and the other is +2.8 × 10-8 C. The points A and B are located 2.5 × 10-3 m from the lower and upper point charges as shown.

-If a proton, which has a charge of +1.60 × 10^-¹⁹ C, is moved from rest at A to rest at B, what is change in electrical potential energy of the proton?

Quizplus · Accepted Answer

The change in electrical potential energy of the proton is given by the equation:ΔU = qΔVwhere:q is the charge of the proton (+1.60 × 10^-19 C)ΔV is the change in electrical potential between points A and BThe change in electrical potential is given by the equation:ΔV = Vb - Vawhere:Vb is the electrical potential at point BVa is the electrical potential at point ASince the proton is moved from rest at A to rest at B, the change in kinetic energy of the proton is zero. Therefore, the change in electrical potential energy of the proton is equal to the negative of the change in potential energy of the proton.ΔU = -ΔK = -0 = 0 JTherefore, the correct answer is E) zero joules.

Two Point Charges Are Separated by 1