A uniform electric field with a magnitude of 125 000 N/C passes through a rectangle with sides of 2.50 m and 5.00 m. The angle between the electric field vector and the vector normal to the rectangular plane is 65.0°. What is the electric flux through the rectangle?

Question

Quizplus · Accepted Answer

The electric flux (Φ) is given by the formula Φ = E * A * cos(θ), where E is the electric field magnitude, A is the area of the rectangle, and θ is the angle between the field and the normal to the surface. Here, E = 125,000 N/C, A = 2.50 m * 5.00 m = 12.5 m², and θ = 65.0°. Thus, Φ = 125,000 * 12.5 * cos(65°) = 6.60 × 10⁵ N·m²/C.

A Uniform Electric Field with a Magnitude of 125 000