A string with a length of 3.0 m has two adjacent resonances at frequencies 112 Hz and 140 Hz.
-What is the wavelength of the first harmonic?
A)0.75 m
B)1.50 m
C)3.00 m
D)6.00 m
E)12.0 m

Question

Quizplus · Accepted Answer

The difference between the two adjacent resonant frequencies (140 Hz - 112 Hz = 28 Hz) is the fundamental frequency. The wavelength of the first harmonic (fundamental frequency) is twice the length of the string, so 2 * 3.0 m = 6.0 m.

A String with a Length of 3