Determine the shortest length of pipe,open at both ends,which will resonate at 256 Hz.The speed of sound is 343 m/s.
A)0.330 m
B)0.670 m
C)0.990 m
D)1.32 m
E)1.67 m

Question

Quizplus · Accepted Answer

For a pipe open at both ends, the fundamental frequency (first harmonic) is given by f = v / (2L), where v is the speed of sound and L is the length of the pipe. Solving for L gives L = v / (2f). Substituting the given values, L = 343 m/s / (2 * 256 Hz) = 0.670 m.

Determine the Shortest Length of Pipe,open at Both Ends,which Will