A periodic transverse wave is established on a string such that there are exactly two cycles traveling along a 3.0-m section of the string. The crests move at 20.0 m/s.
-What is the shortest horizontal distance from a crest to a point of zero acceleration?
A)0.38 m
B)0.75 m
C)1.5 m
D)3.0 m
E)6.0 m

Question

Quizplus · Accepted Answer

The shortest horizontal distance from a crest to a point of zero acceleration is one-quarter of a wavelength. The wavelength is the distance between two consecutive crests or troughs. In this case, there are two cycles traveling along a 3.0-m section of the string, so the wavelength is 3.0 m / 2 = 1.5 m. Therefore, the shortest horizontal distance from a crest to a point of zero acceleration is 1.5 m / 4 = 0.38 m.

A Periodic Transverse Wave Is Established on a String Such