Neglecting air resistance, what maximum height will be reached by an arrow launched straight upward with an initial speed of 35 m/s?
A)98 m
B)160 m
C)41 m
D)63 m
E)18 m

Question

Quizplus · Accepted Answer

We can use the equation for height (h) as a function of time (t) for an object launched vertically upward:
h = v0t - 1/2gt^2
Where v0 is the initial velocity (35 m/s) and g is the acceleration due to gravity (9.81 m/s^2).
To find the maximum height, we need to find the time at which the arrow reaches its maximum height, and then substitute that time into the equation for height.
At the maximum height, the arrow's velocity is zero, so we can use the equation for velocity (v) as a function of time (t) for an object launched vertically upward:
v = v0 - gt
Setting v = 0 and solving for t, we get:
t = v0/g
Substituting v0 = 35 m/s and g = 9.81 m/s^2, we get:
t = 35/9.81 ≈ 3.57 s
Substituting this value of t into the equation for height, we get:
h = (35)(3.57) - 1/2(9.81)(3.57)^2
h ≈ 63 m

Neglecting Air Resistance, What Maximum Height Will Be Reached by an Arrow