A ball is shot straight up from the surface of the earth with an initial speed of 19.6 m/s. Neglect any effects due to air resistance.
-What is the magnitude of the ball's displacement from the starting point after 1.00 second has elapsed?
A)9.80 m
B)14.7 m
C)19.6 m
D)24.5 m
E)58.8 m

Question

A ball is shot straight up from the surface of the earth with an initial speed of 19.6 m/s.  Neglect any effects due to air resistance.
-What is the magnitude of the ball's displacement from the starting point after 1.00 second has elapsed?
A)9.80 m
B)14.7 m
C)19.6 m
D)24.5 m
E)58.8 m

Quizplus · Accepted Answer

Using the formula for displacement in free fall, we have 
d = v0t + (1/2)gt^2, 
where d is displacement, v0 is initial velocity, t is time, and g is acceleration due to gravity. 
Plugging in the values given, we have 
d = (19.6 m/s)(1.00 s) + (1/2)(9.81 m/s^2)(1.00 s)^2 = 14.7 m. 
Thus, the magnitude of the ball's displacement from the starting point after 1.00 second has elapsed is 14.7 m.

A Ball Is Shot Straight Up from the Surface of the Earth