A small object is released from rest and falls 1.00 × 10² feet near the surface of the earth. Neglect air resistance.
-How long will it take to fall through the 1.00 × 10²feet mentioned?

Question

Quizplus · Accepted Answer

Explanation:The distance fallen is given by:$$d = \frac{1}{2}gt^2$$where:d is the distance fallen (in feet)g is the acceleration due to gravity (32.2 ft/s^2)t is the time fallen (in seconds)Solving for t, we get:$$t = \sqrt{\frac{2d}{g}}$$Substituting the given values, we get:$$t = \sqrt{\frac{2(1.00 	imes 10^2 	ext{ ft})}{32.2 	ext{ ft/s}^2}} = 2.49 	ext{ s}$$Therefore, the correct answer is A.

A Small Object Is Released from Rest and Falls 1