A male who is color-blind marries a heterozygous woman.What percent of their male children will be color-blind?

Question

Quizplus · Accepted Answer

Given that X^B= normal color vision and X^b = color blind (recessive), a heterozygous female would be X^BX^b and a color blind man would be X^bY. Daughters would have a 50% chance of inheriting normal color vision but they will be heterozygous for the trait, the other 50% will be color blind. Sons have the same 50/50 chance of normal versus color blind vision. Notice that this is based on the probability of the X chromosome that they will inherit from their mother since the will not receive an X from their father; for daughter it is still the mother's X chromosome that makes the difference since the X chromosome they would inherit from their father must carry the color blind allele.Bloom's

A Male Who Is Color-Blind Marries a Heterozygous Woman