Given the Standard Reaction Enthalpies Below: N₂(g)+ O₂ $\rightarrow$ 2NO(g) $\Delta$ H° = +1805 KJ

Given the standard reaction enthalpies below: N₂(g) + O₂ $\rightarrow$ 2NO(g)
$\Delta$ H° = +180.5 kJ.mol ^{- 1}
2NO₂(g) $\rightarrow$ N₂(g) + 2O₂(g)
$\Delta$ H° = -66.4 kJ.mol ^{- 1}
Calculate the standard reaction enthalpy for the oxidation of nitric oxide to nitrogen dioxide,shown below:
2NO(g) + O₂(g) $\rightarrow$ 2NO₂(g)

A) (-114.1 kJ.mol ^{- 1} )
B) (-246.9 kJ.mol ^{- 1} )
C) (-114.1 kJ.mol ^{- 1} ) .
D) (-294.6 kJ.mol ^{- 1} ) .
E) (-246.9 kJ.mol ^{- 1} ) .