Calculate the vapor pressure at25^$\omicron$C of a mixture of benzene and toluene in which the mole fraction of benzene is 0.650 .The vapor pressure at 25^$\omicron$C of benzene is 94.6 Torr and that of toluene is 29.1 Torr.

Question

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The vapor pressure of the mixture can be calculated using Raoult's Law, which states that the total vapor pressure of a solution is the sum of the vapor pressures of each component multiplied by their respective mole fractions. For benzene (mole fraction = 0.650, vapor pressure = 94.6 Torr) and toluene (mole fraction = 0.350, vapor pressure = 29.1 Torr), the total vapor pressure is (0.650 * 94.6) + (0.350 * 29.1) = 71.7 Torr.

Calculate the Vapor Pressure At25 ο\omicronο C of a Mixture of Benzene and Toluene in Which

Calculate the Vapor Pressure At25^$\omicron$C of a Mixture of Benzene and Toluene in Which