At 600$\degree$C,the equilibrium constant for the reaction 2HgO(s) 2Hg(l)+ O 2 (g) Is 2.8.Calculate the equilibrium constant for the reaction 1/2O 2 (g)+ Hg(l) HgO(s)

Using the equilibrium constant expression: Kc = [Hg]²[O₂]/ [HgO]² = (p[Hg]/RT)²(p[O₂]/RT) / ([HgO]/RT)² = (p[Hg]²/p[HgO]²) (p[O₂]/RT) = (1.4²/2.8) (0.20) (at 600°C, R = 0.08206 L atm/(mol K)) = 0.60

At 600$\degree$C,the equilibrium constant for the reaction 2HgO(s) 2Hg(l)+ O 2 (g) Is 2.8.Calculate the equilibrium constant for the reaction 1/2O 2 (g)+ Hg(l) HgO(s)

Using the equilibrium constant expression: Kc = [Hg]²[O₂]/ [HgO]² = (p[Hg]/RT)²(p[O₂]/RT) / ([HgO]/RT)² = (p[Hg]²/p[HgO]²) (p[O₂]/RT) = (1.4²/2.8) (0.20) (at 600°C, R = 0.08206 L atm/(mol K)) = 0.60

Solved

At 600 $\degree$ C,the Equilibrium Constant for the Reaction 2HgO(s) 2Hg(l)+ O₂(g)

Question 34

Multiple Choice

At 600 $\degree$ C,the equilibrium constant for the reaction 2HgO(s) $At 600 \degree C,the equilibrium constant for the reaction 2HgO(s) 2Hg(l) + O2(g) Is 2.8.Calculate the equilibrium constant for the reaction 1/2O2(g) + Hg(l) HgO(s) A) (-1.7) B) 1.1 C) 0.60 D) 0.36 E) 1.7$ 2Hg(l) + O₂(g)
Is 2.8.Calculate the equilibrium constant for the reaction $At 600 \degree C,the equilibrium constant for the reaction 2HgO(s) 2Hg(l) + O2(g) Is 2.8.Calculate the equilibrium constant for the reaction 1/2O2(g) + Hg(l) HgO(s) A) (-1.7) B) 1.1 C) 0.60 D) 0.36 E) 1.7$ 1/2O₂(g) + Hg(l) $At 600 \degree C,the equilibrium constant for the reaction 2HgO(s) 2Hg(l) + O2(g) Is 2.8.Calculate the equilibrium constant for the reaction 1/2O2(g) + Hg(l) HgO(s) A) (-1.7) B) 1.1 C) 0.60 D) 0.36 E) 1.7$ HgO(s)