For the titration of 50.0 mL of 0.020 M aqueous salicylic acid with 0.020 M KOH(aq),calculate the pH after the addition of 55.0 mL of KOH(aq).For salycylic acid,pK_a = 2.97.

Question

Quizplus · Accepted Answer

The correct answer is A because the pH of the solution after the addition of 55.0 mL of KOH(aq) is 10.98. This is because the salicylic acid is a weak acid and the KOH is a strong base, so the reaction will go to completion and the salicylic acid will be completely neutralized. The pH of the solution will then be determined by the concentration of the acetate ion, which is the conjugate base of the salicylic acid. The pKa of salicylic acid is 2.97, so the pH of the solution will be 10.98.

For the Titration of 50