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-The galvanic cell shown above uses the half-cells Pb²⁺/Pb and Zn²⁺/Zn,and a salt bridge containing KCl(aq).The voltmeter gives a positive voltage reading.The electrode B could be inert platinum metal or lead.

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-The galvanic cell shown above uses the half-cells Pb²⁺/Pb and Zn²⁺/Zn,and a salt bridge containing KCl(aq).The voltmeter gives a positive voltage reading.The electrode B could be inert platinum metal or lead.

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Since the voltmeter gives a positive voltage reading, we know that the reaction is spontaneous and the standard cell potential is positive. Therefore, the reaction is occurring in the direction from the anode to the cathode. The anode is the electrode where oxidation occurs, and the cathode is the electrode where reduction occurs. In this case, Pb is being oxidized at the anode and Zn is being reduced at the cathode. If electrode B could be an inert platinum metal, it would not affect the cell potential as it is not participating in the reaction. However, if electrode B is lead, it would react with PbS and affect the cell potential. Therefore, the statement "electrode B could be inert platinum metal or lead" is true.

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