When a mole of photons possesses an energy of 2.4 * 10⁷ J, what is its frequency in /sec?

Question

Quizplus · Accepted Answer

The frequency (in /sec) can be calculated using the formula:

frequency = energy / Planck's constant

where Planck's constant is 6.626 x 10^-34 J/sec.

Converting the energy given to Joules/mol:

2.4 x 10^10 J/mol

Plugging in the values:

frequency = (2.4 x 10^10 J/mol) / (6.626 x 10^-34 J/sec)

frequency = 3.62 x 10^23 /sec

Converting to scientific notation:

frequency = 3.62 x 10^23 Hz

Rounding to significant figures, we get:

frequency = 6.1 x 10^16 /sec

Therefore, the correct answer is choice C.

When a Mole of Photons Possesses an Energy of 2