Calculate the density of camphor, C 10 H 16 O, At 80 $\omicron $ C and 12 Torr.

Question

Quizplus · Accepted Answer

The density of a substance can be calculated using the formula: 
density = (molecular weight * pressure) / (gas constant * temperature)
First, we need to convert the temperature from 80°F to 26.67°C using the conversion formula (C° = (F°-32) * (5/9)). This gives us a temperature of 26.67°C.
Next, we need to convert the molecular weight of camphor from the given formula to its numeric value. Using a periodic table, we find that camphor has a molecular weight of approximately 152.23 g/mol.
Plugging in the given values, we get: 
density = (152.23 g/mol * 12 Torr) / (62.364 L·mmHg/mol·K * 26.67°C)
Simplifying the units, we get:
density = (152.23 g/mol * 12/760 atm) / (0.082057 L·atm/mol·K * 299.82 K)
density = 0.083 g/cm³
Therefore, the answer is B.

Calculate the Density of Camphor, C10H16O, at 80 ο\omicron ο C and 12 Torr

Calculate the Density of Camphor, C₁₀H₁₆O, at 80^$\omicron$C and 12 Torr