Consider the following van der Waals coefficients: $$\begin{array} { | l | l | l | }
\hline \text { Gas } & \mathrm { a } , \mathrm { L } ^ { 2 } \text { atm } \mathrm { mol } ^ { - 2 } & \mathrm {~b} , \mathrm {~L} \cdot \mathrm { mol } ^ { - 1 } \
\hline \text { helium } & 0.034 & 0.0237 \
\hline \text { hydrogen } & 0.244 & 0.0266 \
\hline \text { neon } & 0.211 & 0.0171 \\hline \text { krypton } & 2.32 & 0.0398 \
\hline \text { xenon } & 4.19 & 0.0511 \
\hline \text { chlorine } & 6.49 & 0.0562 \\hline \text { carbon diozide } & 3.59 & 0.0427 \
\hline \text { ammonia } & 4.17 & 0.0371 \
\hline \text { water } & 5.46 & 0.0305 \
\hline
\end{array}$$ Which of the following gases has the smallest attractive forces?

Question

Consider the following van der Waals coefficients: $$\begin{array} { | l | l | l | } 
\hline \text { Gas } & \mathrm { a } , \mathrm { L } ^ { 2 } \text { atm } \mathrm { mol } ^ { - 2 } & \mathrm {~b} , \mathrm {~L} \cdot \mathrm { mol } ^ { - 1 } \
\hline \text { helium } & 0.034 & 0.0237 \
\hline \text { hydrogen } & 0.244 & 0.0266 \
\hline \text { neon } & 0.211 & 0.0171 \\hline \text { krypton } & 2.32 & 0.0398 \
\hline \text { xenon } & 4.19 & 0.0511 \
\hline \text { chlorine } & 6.49 & 0.0562 \\hline \text { carbon diozide } & 3.59 & 0.0427 \
\hline \text { ammonia } & 4.17 & 0.0371 \
\hline \text { water } & 5.46 & 0.0305 \
\hline
\end{array}$$ Which of the following gases has the smallest attractive forces?

Quizplus · Accepted Answer

The van der Waals coefficient "a" represents the magnitude of the attractive forces between gas molecules. The smaller the value of "a," the weaker the attractive forces. Helium has the smallest "a" value (0.034), indicating it has the smallest attractive forces among the listed gases.

Consider the Following Van Der Waals Coefficients Which of the Following Gases Has the Smallest Attractive Forces