Calculate the final temperature when 2.50 kJ of energy is transferred as heat to 1.50 mol BF₃ at 298 K and 1 atm at constant volume.

Question

Quizplus · Accepted Answer

The heat transferred can be calculated using the equation q = nCvΔT, where q is the heat transferred, n is the number of moles of the substance, Cv is the molar heat capacity at constant volume, and ΔT is the change in temperature. Since the volume is constant, ΔT = q/(nCv). The molar heat capacity at constant volume for BF₃ is approximately 12.5 J/(mol*K). Thus, ΔT = (2.50 kJ)/(1.50 mol*12.5 J/(mol*K)) = 133.33 K. The final temperature can be calculated as Tfinal = 298 K + ΔT = 431.33 K = 92°C. Therefore, the answer is choice E, 92°F.

Calculate the Final Temperature When 2 ∘\circ∘ C B) 80 ∘\circ∘ C C) 67

Calculate the Final Temperature When 2 $\circ$ C
B) 80^$\circ$C
C) 67