For any isothermal process, $\Delta$U 0 for an ideal gas.

Question

For any isothermal process, $\Delta$U > 0 for an ideal gas.

Quizplus · Accepted Answer

For an isothermal process, the internal energy of an ideal gas remains constant. Therefore, ΔU = 0. So F1F1F1S1 = ΔQ and for an isothermal process, ΔQ = nRTln(V2/V1), where n is the number of moles, R is the gas constant, T is the temperature and V1 and V2 are the initial and final volumes respectively. As ln(V2/V1) > 0, ΔQ > 0. Therefore, F1F1F1S1 > 0 for an isothermal process of an ideal gas.

For Any Isothermal Process Δ\DeltaΔ U > 0 for an Ideal Gas

For Any Isothermal Process $\Delta$ U > 0 for an Ideal Gas