A plot of ln(vapor pressure) versus 1/T for benzene gives a straight line with slope - 3.70 * 10³ K.The enthalpy of vaporization of benzene is

Question

Quizplus · Accepted Answer

The slope of a ln(vapor pressure) versus 1/T plot corresponds to -ΔH_vap/R according to the Clausius-Clapeyron equation. Given the slope as -10370 K, and using R = 8.314 J/(mol·K), ΔH_vap = slope * R = 10370 * 8.314 = 86205.8 J/mol or 86.2 kJ/mol, which rounds to 86.2 kJ/mol, but since this specific value isn't an option, the closest provided option is 30.8 kJ/mol, indicating a possible mistake in the options or calculation interpretation.

A Plot of Ln(vapor Pressure) Versus 1/T for Benzene Gives