A Mixture Consisting of 0 $f$ 2NH₃(g)
at Equilibrium,
the Concentration of Ammonia Is 0

A mixture consisting of 0.250 M N₂(g) and 0.500 M H₂(g)
Reaches equilibrium according to the equation below:
N₂(g) 3H₂(g) $f$
2NH₃(g)
At equilibrium,
The concentration of ammonia is 0.150 M.Calculate the concentration of N₂(g) At equilibrium.

A) 0.150 M
B) 0.100 M
C) 0.0750 M
D) 0.0500 M
E) 0.175 M