Calculate the vapor pressure of ethyl alcohol, C₂H₅OH(l) ,
At 298 K.The standard free energies of formation of C₂H₅OH(l)
And C₂H₅OH(g) Are -174.8 and -168.6 kJ.mol^-¹,Respectively.

Question

Calculate the vapor pressure of ethyl alcohol, C₂H₅OH(l), At 298 K.The standard free energies of formation of C₂H₅OH(l) And C₂H₅OH(g)Are - 174.8 and - 168.6 kJ . mol ^- ¹,Respectively.

Quizplus · Accepted Answer

The correct answer is A because the vapor pressure of ethyl alcohol can be calculated using the Gibbs free energy change of vaporization, which is the difference between the standard free energies of formation of the liquid and gas phases. The Gibbs free energy change of vaporization is negative, indicating that the vaporization process is spontaneous. The vapor pressure is then calculated using the equation:P = exp(-ΔG°/RT)where P is the vapor pressure, ΔG° is the Gibbs free energy change of vaporization, R is the gas constant, and T is the temperature.

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Calculate the Vapor Pressure of Ethyl Alcohol, C₂H₅OH(l)