A 0.0010 M solution of a weak acid, HA,With Ka = 2 * 10-10 produces [H3O+] < 10-6 M.Which of the following equations can be used to determine [H3O+]?
A) The acid is so weak that the pH is about 7.
B) [H3O+]2 + Ka [H3O+] - [HA]initialKa = 0
C) [H3O+] = (Kw + Ka[HA]initial) ½
D) [H3O+] = [HA]initial
E) [H3O+] = (Ka[HA]initial) ½
Correct Answer:
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