For the reduction of Cu²⁺ by Zn,
$\Delta$ G^o = -212 kJ/mol and E^o = +1.10 V.If the coefficients in the chemical equation for this reaction are multiplied by 2, $\Delta$ G^o = -424 kJ/mol.This means E^o = +2.20 V.

Question

For the reduction of Cu²⁺ by Zn,

\Delta

G^o = -212 kJ/mol and E^o = +1.10 V.If the coefficients in the chemical equation for this reaction are multiplied by 2,

\Delta

G^o = -424 kJ/mol.This means E^o = +2.20 V.

Quizplus · Accepted Answer

Doubling the coefficients in a chemical equation doubles the value of $\Delta G$, but the cell potential $E$ remains unchanged because it is an intensive property that does not depend on the amount of substance involved in the reaction.

For the Reduction of Cu2+ by Zn Δ\DeltaΔ Go = -212 KJ/mol and Eo = +1

For the Reduction of Cu²⁺ by Zn $\Delta$ G^o = -212 KJ/mol and E^o = +1