The U-238 decay series ends at Pb-206 .Which processes are used in this radioactive series to reach Pb-206?

Question

Quizplus · Accepted Answer

The U-238 decay series involves a series of alpha (α) and beta (β) decays. The alpha decay results in the loss of a helium nucleus, which reduces the mass number by 4 and atomic number by 2. The beta decay involves the transformation of a neutron into a proton, which increases the atomic number by 1. The U-238 decay series involves a total of 14 alpha decay and 5 beta decay steps, resulting in the formation of Pb-206 as the stable end product. Therefore, Choice C, which involves both alpha and beta decay processes, is the correct answer.

The U-238 Decay Series Ends at Pb-206 α\alphaα -Particle and Positron Emission B)

The U-238 Decay Series Ends at Pb-206 $\alpha$ -Particle and Positron Emission
B)