An iron mine produces 2.18 × 10⁵ US tons of raw ore on a daily basis which contains 21.47% elemental iron.How many pounds of elemental iron would the mine produce over a span of one year? (Assume the mine operates 365 days per year.)(1 US ton = 2000 lbs.) A)1.59 × 10¹¹ B)7.96 × 10⁷ C)3.42 × 10¹⁰ D)1.71 × 10⁷ E)4.68 × 10⁴

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First, calculate the daily production of elemental iron in tons: 2.18 × 10^5 tons × 21.47% = 4.68 × 10^4 tons. Convert this to pounds: 4.68 × 10^4 tons × 2000 lbs/ton = 9.36 × 10^7 lbs. Multiply by 365 days to find the annual production: 9.36 × 10^7 lbs/day × 365 days = 3.42 × 10^10 lbs.

An Iron Mine Produces 2