The combustion of propane (C₃H₈)produces CO₂ and H₂O: C₃H₈(g)+ 5O₂ (g)→ 3CO₂ (g)+ 4H₂O (g) The reaction of 2.5 mol of O₂with 4.6 mol of C₃H₈will produce ________ mol of H₂O.

Question

Quizplus · Accepted Answer

According to the balanced equation, for every 5 moles of O₂ consumed, 4 moles of H₂O are produced. Therefore, we can first find the limiting reactant: 2.5 mol O₂ × (1 mol C₃H₈ / 5 mol O₂) = 0.5 mol C₃H₈ Since 0.5 mol is less than the 4.6 mol of C₃H₈given, C₃H₈ is the limiting reactant. We can use stoichiometry to find the amount of H₂O produced: 4.6 mol C₃H₈ × (4 mol H₂O / 3 mol C₃H₈) = 6.133... ≈ 6.1 mol H₂O Rounding to the correct number of significant figures gives us 2.0 mol H₂O, so the answer is D.

The Combustion of Propane (C3H8)produces CO2 and H2O: C3H8 (g)

The Combustion of Propane (C₃H₈)produces CO₂ and H₂O: C₃H₈(g)