Pentacarbonyliron (Fe(CO)₅)reacts with phosphorous trifluoride (PF₃)and hydrogen,releasing carbon monoxide: Fe(CO)₅ + PF₃ + H₂ → Fe(CO)₂(PF₃)₂(H)₂ + CO (not balanced) The reaction of 9.0 mol of Fe(CO)₅,11.0 mol of PF₃ and 3.0 mol of H₂ will release ________ mol of CO. A)9 B)3 C)27 D)16.5 E)23

Question

Quizplus · Accepted Answer

The balanced equation is: Fe(CO)₅ + 2PF₃ + 2H₂ → Fe(CO)₂(PF₃)₂(H)₂ + 3CO9 mol of Fe(CO)₅ will react with 18 mol of PF₃ and 18 mol of H₂ to produce 27 mol of CO.Since only 11 mol of PF₃ and 3 mol of H₂ are available, they will be the limiting reactants.11 mol of PF₃ will react with 11 mol of Fe(CO)₅ and 11 mol of H₂ to produce 16.5 mol of CO.Therefore, the correct answer is A) 9.

Pentacarbonyliron (Fe(CO)5)reacts with Phosphorous Trifluoride (PF3)and Hydrogen,releasing Carbon Monoxide: Fe(CO)5

Pentacarbonyliron (Fe(CO)₅)reacts with Phosphorous Trifluoride (PF₃)and Hydrogen,releasing Carbon Monoxide: Fe(CO)₅