Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li (s) + N₂(g) → 2Li₃N (s)
How many moles of lithium are needed to produce 0.45 mol of Li₃N when the reaction is carried out in the presence of excess nitrogen?

Question

Quizplus · Accepted Answer

From the balanced chemical equation, we can see that 6 moles of lithium react with 1 mole of nitrogen to produce 2 moles of lithium nitride. Therefore, we can set up a proportion:

6 mol Li / 2 mol Li3N = x mol Li / 0.45 mol Li3N

Simplifying the proportion, we get:

x = 1.4 mol Li

Therefore, we need 1.4 moles of lithium to produce 0.45 mol of Li3N. The answer is B.

Lithium and Nitrogen React in a Combination Reaction to Produce