The value of ΔH° for the reaction below is -336 kJ.Calculate the heat (kJ)released to the surroundings when 23.0 g of HCl is formed. CH₄ (g)+ 3Cl₂ (g)→ CHCl₃ (l)+ 3HCl (g) A)177 kJ B)2.57 × 10³ kJ C)70.7 kJ D)211 kJ E)-336 kJ

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Quizplus · Accepted Answer

The molar mass of HCl is approximately 36.5 g/mol. Therefore, 23.0 g of HCl corresponds to 23.0 g / 36.5 g/mol = 0.63 mol. Since the ΔH° for the reaction is -336 kJ per mole of reaction as written, and the reaction produces 3 moles of HCl for every 1 mole of reaction, the heat released for 0.63 mol of HCl is (0.63 mol HCl / 3 mol HCl per mole of reaction) * -336 kJ/mol = -70.7 kJ.

The Value of ΔH° for the Reaction Below Is -336