The specific heat capacity of lead is 0.13 J/g-K.How much heat (in J)is required to raise the temperature of of lead from 22 °C to 37 °C?

Question

The specific heat capacity of lead is 0.13 J/g-K.How much heat (in J)is required to raise the temperature of  of lead from 22 °C to 37 °C?

Quizplus · Accepted Answer

The formula to calculate the amount of heat required is:

Q = m * c * ΔT

where 
Q = heat required (in J)
m = mass of the substance (in g)
c = specific heat capacity (in J/g-K)
ΔT = change in temperature (in K or °C)

Substituting the given values, we get:

Q = 11ea7e7c_6111_760a_9a0a_d153d38214fc_TB1194_11 * 0.13 * (37 - 22)
Q = 29 J

Therefore, the best choice is D, 29 J.

The Specific Heat Capacity of Lead Is 0